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(B) Given the ratio of intensities $I_1 / I_2 = 9 / 1$.Since intensity $I \propto A^2$, the ratio of amplitudes is $A_1 / A_2 = \sqrt{I_1 / I_2} = \sq

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$4: 1$

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(B) Given the ratio of intensities $I_1 / I_2 = 9 / 1$.Since intensity $I \propto A^2$, the ratio of amplitudes is $A_1 / A_2 = \sqrt{I_1 / I_2} = \sqrt{9 / 1} = 3 / 1$.Let $A_1 = 3k$ and $A_2 = k$.The intensity of maxima is given by $I_{\max} = (A_1 + A_2)^2 = (3k + k)^2 = (4k)^2 = 16k^2$.The intensity of minima is given by $I_{\min} = (A_1 - A_2)^2 = (3k - k)^2 = (2k)^2 = 4k^2$.Therefore, the ratio of intensities of maxima and minima is $I_{\max} / I_{\min} = 16k^2 / 4k^2 = 4 / 1$.

The light beams of intensities in the ratio of $9: 1$ are allowed to interfere. What will be the ratio of the intensities of maxima and minima?

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