The line lx + my + n = 0 will be parallel to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general equation of a line is $lx + my + n = 0$.For a line to be parallel to the $x$-axis,its slope must be $0$.The slope of the line $lx + my

Vedclass · Accepted Answer

$l = 0$

Vedclass · Answer

(D) The general equation of a line is $lx + my + n = 0$.For a line to be parallel to the $x$-axis,its slope must be $0$.The slope of the line $lx + my + n = 0$ is given by $m_{slope} = -\frac{l}{m}$.Setting the slope to $0$,we get $-\frac{l}{m} = 0$,which implies $l = 0$ (provided $m 
eq 0$).Thus,the equation becomes $my + n = 0$,or $y = -\frac{n}{m}$,which represents a line parallel to the $x$-axis.

The line $lx + my + n = 0$ will be parallel to the $x$-axis,if

Similar Questions

Find the equation of the line,which cuts off intercepts on the axes whose sum and product are $1$ and $-6,$ respectively.

The equation of the line passing through the point $(2,3)$ such that its $x$-intercept is twice its $y$-intercept is ......... .

Find the equation of the line parallel to the line $3x - 4y + 2 = 0$ and passing through the point $(-2, 3).$

Find the slope of the line,which makes an angle of $30^{\circ}$ with the positive direction of the $y$-axis measured anticlockwise.

Find the equation of the line perpendicular to the line $2x - 3y = 5$ and passing through the point $(1, -1)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module