The linear momentum p of a body of mass 5 ,kg | vedclass

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(C) Given the linear momentum $p = 5t^2 + t + 5$ and mass $m = 5 \,kg$.Since $p = mv$,we have $v = \frac{p}{m} = \frac{5t^2 + t + 5}{5} = t^2 + 0.2t +

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variable acceleration which is increasing with time

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(C) Given the linear momentum $p = 5t^2 + t + 5$ and mass $m = 5 \,kg$.Since $p = mv$,we have $v = \frac{p}{m} = \frac{5t^2 + t + 5}{5} = t^2 + 0.2t + 1$.The acceleration $a$ is the rate of change of velocity with respect to time: $a = \frac{dv}{dt} = \frac{d}{dt}(t^2 + 0.2t + 1) = 2t + 0.2$.As time $t$ increases,the acceleration $a = 2t + 0.2$ also increases linearly with time.Therefore,the body is moving with variable acceleration which is increasing with time.

The linear momentum $p$ of a body of mass $5 \,kg$ varies with time $t$ as $p = 5t^2 + t + 5$. It follows that the body is moving with:

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