The lines $2x + 3y = 6$ and $2x + 3y = 8$ cut the $X$-axis at $A$ and $B$,respectively. $A$ line $L$ drawn through the point $(2, 2)$ meets the $X$-axis at $C$ in such a way that the abscissae of $A, B,$ and $C$ are in arithmetic progression. Then,the equation of the line $L$ is

  • A
    $2x + 3y = 10$
  • B
    $8x + 2y = 10$
  • C
    $2x - 3y = 10$
  • D
    $8x - 2y = 10$

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