The opposite vertices of a square are $(1, 2)$ and $(3, 8)$. Then,the equation of the diagonal of the square passing through the point $(1, 2)$ is:
- A$3x - y - 1 = 0$
- B$3y - x - 1 = 0$
- C$3x + y + 1 = 0$
- DNone of these
Explore More
Similar Questions
The point $P(a, b)$ lies on the straight line $3x + 2y = 13$ and the point $Q(b, a)$ lies on the straight line $4x - y = 5$. Then the equation of the line $PQ$ is
The points $A (1, 3)$ and $C (5, 1)$ are the opposite vertices of a rectangle. The equation of the line passing through the other two vertices and having a gradient of $2$ is:
Easy
View SolutionThe equation of the line passing through $(1, 1)$ and parallel to the line $2x + 3y - 7 = 0$ is
Easy
View SolutionThe equation of a straight line passing through the points $(-5, -6)$ and $(3, 10)$ is:
Easy
View SolutionFind the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point $(2,3)$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo