The lines $\frac{x - 2}{1} = \frac{y - 3}{1} = \frac{z - 4}{-k}$ and $\frac{x - 1}{k} = \frac{y - 4}{2} = \frac{z - 5}{1}$ are coplanar if

  • A
    $k = 0, -3$
  • B
    $k = -1, 3$
  • C
    $k = 1, -3$
  • D
    $k = 2, 4$

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