The logical statement (p Rightarrow q) wedge | vedclass

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(C) The given logical statement is $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow \sim p)$.Using the implication law $a \Rightarrow b \equiv \sim a \vee

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$\sim p$

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(C) The given logical statement is $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow \sim p)$.Using the implication law $a \Rightarrow b \equiv \sim a \vee b$,we get:$(\sim p \vee q) \wedge (\sim q \vee \sim p)$By the commutative law,we can rewrite this as:$(\sim p \vee q) \wedge (\sim p \vee \sim q)$Using the distributive law $x \vee (y \wedge z) \equiv (x \vee y) \wedge (x \vee z)$,we get:$\sim p \vee (q \wedge \sim q)$Since $q \wedge \sim q$ is a contradiction $(C)$:$\sim p \vee C \equiv \sim p$Therefore,the statement is equivalent to $\sim p$.

The logical statement $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow \sim p)$ is equivalent to

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