The logical statement (p lor q) land [(sim p | vedclass

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(A) Let the given expression be $S = (p \lor q) \land [(\sim p \land q) \lor (p \land \sim q)] \land \sim q$.Using the associative property, we can wr

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$p \land \sim q$

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(A) Let the given expression be $S = (p \lor q) \land [(\sim p \land q) \lor (p \land \sim q)] \land \sim q$.Using the associative property, we can write $S = (p \lor q) \land \sim q \land [(\sim p \land q) \lor (p \land \sim q)]$.First, evaluate $(p \lor q) \land \sim q$. By the distributive law, this is $(p \land \sim q) \lor (q \land \sim q)$. Since $(q \land \sim q) = F$ (a contradiction), this simplifies to $(p \land \sim q) \lor F = (p \land \sim q)$.Now substitute this back into $S$: $S = (p \land \sim q) \land [(\sim p \land q) \lor (p \land \sim q)]$.Let $A = (p \land \sim q)$. Then $S = A \land [(\sim p \land q) \lor A]$.By the absorption law, $A \land (B \lor A) = A$.Therefore, $S = A = (p \land \sim q)$.

The logical statement $(p \lor q) \land [(\sim p \land q) \lor (p \land \sim q)] \land \sim q$ is logically equivalent to ...

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