The magnetic moment for two complexes of empirical formula $Ni(NH_3)_4(NO_3)_2 \cdot 2H_2O$ is $0$ and $2.84 \ BM$ respectively. The second complex is not a neutral complex. The correct formula and geometry of the first complex is:

  • A
    $[Ni(H_2O)_2(NO_3)_2] \cdot 4NH_3 = \text{Tetrahedral}$
  • B
    $[Ni(NH_3)_4](NO_3)_2 \cdot 2H_2O = \text{Tetrahedral}$
  • C
    $[Ni(NH_3)_4](NO_3)_2 \cdot 2H_2O = \text{Square planar}$
  • D
    $[Ni(NH_3)_4(H_2O)_2](NO_3)_2 = \text{Octahedral}$

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