The magnetic susceptibility of a material of a rod is $349$ and the permeability of vacuum $\mu_0$ is $4 \pi \times 10^{-7} \ SI$ units. The absolute permeability of the material of the rod in $SI$ units is:

$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, A/m$. As a result,a magnetic moment of $5 \, A \cdot m^2$ is produced in the rod. The value of the total magnetic induction will be (in $Tesla$):

An iron rod is placed parallel to a magnetic field of intensity $H = 2000 \text{ A/m}$. The magnetic flux through the rod is $\phi = 6 \times 10^{-4} \text{ Wb}$ and its cross-sectional area is $A = 3 \text{ cm}^2$. The magnetic permeability $\mu$ of the rod in $\text{Wb/A} \cdot \text{m}$ is:

If $\mu_0$ is the permeability of vacuum and $\chi_m$ is the magnetic susceptibility, then the permeability of the material $\mu$ is . . . . . . .

An iron rod is placed parallel to a magnetic field intensity of $1000 \text{ A/m}$. The magnetic flux through the rod is $3 \times 10^{-4} \text{ Wb}$ and its cross-sectional area is $1.5 \text{ cm}^2$. The magnetic permeability of the rod in $\text{Wb/(A} \cdot \text{m)}$ is:

Give the unit and dimensional formula of magnetisation.