If $\mu_0$ is the permeability of vacuum and $\chi_m$ is the magnetic susceptibility, then the permeability of the material $\mu$ is . . . . . . .

  • A
    $\mu = \mu_0(1 + \chi_m)$
  • B
    $\mu = \mu_0(\chi_m - 1)$
  • C
    $\mu = \mu_0(1 - \chi_m)$
  • D
    $\mu = \mu_0(1 + \chi_m^2)$

Explore More

Similar Questions

The relative permeability of iron is $5500$. What will be its magnetic susceptibility?

The dimensions of magnetic intensity are

$ \chi_{1} $ and $ \chi_{2} $ are the magnetic susceptibilities of a paramagnetic material at temperatures $ T_{1} \ K $ and $ T_{2} \ K $ respectively. Then:

The value of aluminium susceptibility is $2.2 \times 10^{-5}$. The percentage increase in the magnetic field if space within a current-carrying toroid is filled with aluminium is $\frac{x}{10^{4}}$. Then the value of $x$ is ...... .

The magnetic moment produced in a sample of $2 \text{ g}$ is $8 \times 10^{-7} \text{ A} \cdot \text{m}^2$. If its density is $4 \text{ g/cm}^3$, then the magnetization of the sample is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo