The magnitude of crystal field stabilisation | vedclass

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(A) The magnitude of crystal field splitting energy $(\Delta_o)$ in an octahedral complex depends on several factors:$1.$ The nature of the ligand: St

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$I, II, III$ only correct

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(A) The magnitude of crystal field splitting energy $(\Delta_o)$ in an octahedral complex depends on several factors:$1.$ The nature of the ligand: Strong field ligands cause larger splitting than weak field ligands.$2.$ The charge on the metal ion: Higher oxidation states of the metal ion lead to greater splitting.$3.$ The transition series: The splitting energy increases as we move down a group (from $3d$ to $4d$ to $5d$ series) because the $d$-orbitals become more extended and interact more strongly with ligands.Therefore,all three factors $(I, II, III)$ influence the magnitude of the crystal field stabilisation energy.

List-$I$	List-$II$
$P$. $t_{2g}^6 e_g^0$	$1$. $[Fe(H_2O)_6]^{2+}$
$Q$. $t_{2g}^3 e_g^2$	$2$. $[Mn(H_2O)_6]^{2+}$
$R$. $e^2 t_2^3$	$3$. $[Co(NH_3)_6]^{3+}$
$S$. $t_{2g}^4 e_g^2$	$4$. $[FeCl_4]^{-}$
	$5$. $[CoCl_4]^{2-}$

The magnitude of crystal field stabilisation energy in octahedral field depends on :
$I.$ The nature of the ligand
$II.$ The charge on the metal ion
$III.$ Whether the metal is in the first,second or third row of the transition elements

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The magnitude of crystal field stabilisation energy in octahedral field depends on :$I.$ The nature of the ligand$II.$ The charge on the metal ion$III.$ Whether the metal is in the first,second or third row of the transition elements