The magnitude of magnetic fields at a distanc | vedclass

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(B) For a short bar magnet of magnetic moment $M$,the magnetic field at a distance $r$ on the axial (longitudinal) line is given by $B_{axial} = \frac

Vedclass · Accepted Answer

$2:1$

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(B) For a short bar magnet of magnetic moment $M$,the magnetic field at a distance $r$ on the axial (longitudinal) line is given by $B_{axial} = \frac{\mu_{0}}{4\pi} \frac{2M}{r^{3}}$.For the same distance $r$ on the equatorial (transverse) line,the magnetic field is given by $B_{equatorial} = \frac{\mu_{0}}{4\pi} \frac{M}{r^{3}}$.Taking the ratio of the magnetic field in the longitudinal position to the transverse position:$\frac{B_{axial}}{B_{equatorial}} = \frac{\frac{\mu_{0}}{4\pi} \frac{2M}{r^{3}}}{\frac{\mu_{0}}{4\pi} \frac{M}{r^{3}}} = \frac{2}{1}$.Therefore,the ratio is $2:1$.

The magnitude of magnetic fields at a distance $r$ from the centre of a short bar magnet,in longitudinal position to transverse position,is in the ratio:

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