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(C) The reaction involves the radical chlorination of the given compound in the presence of excess $Cl_2$ and $h
u$. Both the benzylic positions are

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(C) The reaction involves the radical chlorination of the given compound in the presence of excess $Cl_2$ and $h
u$. Both the benzylic positions are reactive. The $Ph_2CH-$ group has a benzylic hydrogen which is highly reactive and gets substituted by $Cl$ to form $Ph_2CCl-$. The $-CH_3$ group attached to the phenyl ring is also a benzylic position,which undergoes exhaustive chlorination to form a $-CCl_3$ group. Thus,the final product is $Ph_2CCl-C_6H_4-CCl_3$.

The main product of the following reaction is:

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