The major product B formed in the following r | vedclass

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(D) Step $1$: The reaction of $p-methoxybenzaldehyde$ with $C_2H_5MgBr$ followed by hydrolysis $(H_2O)$ is a Grignard reaction. The nucleophilic ethyl

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$1-(1-Chloropropyl)-4-methoxybenzene$

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(D) Step $1$: The reaction of $p-methoxybenzaldehyde$ with $C_2H_5MgBr$ followed by hydrolysis $(H_2O)$ is a Grignard reaction. The nucleophilic ethyl group attacks the carbonyl carbon to form a secondary alcohol,$A$,which is $1-(4-methoxyphenyl)propan-1-ol$.Step $2$: The reaction of $A$ with $HCl$ proceeds via an $S_N1$ mechanism. The hydroxyl group is protonated to form a good leaving group $(H_2O)$,which leaves to form a stable benzylic carbocation. The chloride ion then attacks this carbocation to form the major product $B$,which is $1-(1-chloropropyl)-4-methoxybenzene$.

The major product $B$ formed in the following reaction sequence is
$p-Methoxybenzaldehyde$ $\xrightarrow[(ii) H_2O]{(i) C_2H_5MgBr} A$ $\xrightarrow{HCl} B$

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The major product $B$ formed in the following reaction sequence is$p-Methoxybenzaldehyde$ $\xrightarrow[(ii) H_2O]{(i) C_2H_5MgBr} A$ $\xrightarrow{HCl} B$