The major product of the following reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Treatment with aqueous $KOH$ performs nucleophilic substitution of the primary alkyl bromide to form a primary alcohol,$3-(3-bromophenyl

Vedclass · Accepted Answer

$6-$bromo$-1-$indanone

Vedclass · Answer

(A) Step $1$: Treatment with aqueous $KOH$ performs nucleophilic substitution of the primary alkyl bromide to form a primary alcohol,$3-(3-bromophenyl)propan-1-ol$.Step $2$: Oxidation with $CrO_3/H^+$ (Jones reagent) converts the primary alcohol into a carboxylic acid,$3-(3-bromophenyl)propanoic acid$.Step $3$: Intramolecular Friedel-Crafts acylation using $H_2SO_4/\Delta$ leads to cyclization. The carboxylic acid group attacks the ortho position relative to the alkyl chain. Since the meta-bromo group directs the cyclization,the product formed is $6-bromo-1-indanone$.

The major product of the following reaction is:

Similar Questions

What is the product formed when ethyl acetate reacts with an excess of $CH_3MgI$ followed by hydrolysis?

$CH_3CO_2C_2H_5$ on reaction with sodium ethoxide in ethanol gives $A$,which on heating in the presence of acid gives $B$. Compound $B$ is

When propionic acid is reacted with aqueous sodium carbonate,$CO_2$ is released. From where does the $'C'$ of $CO_2$ come?

Which reaction is not possible for acetic anhydride?

The decreasing order of nucleophilicity among the following nucleophiles is:
$(I)$ $CH_3-COO^{-}$
$(II)$ $CH_3O^{-}$
$(III)$ $C_6H_5O^{-}$
$(IV)$ $CH_3-SO_3^-$

Vedclass Test Series

Exam Paper Generator

Online Exam Module