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(B) The reaction proceeds as follows:$1$. The starting material is $6$-chlorocyclohex-$2$-en-$1$-one.$2$. Addition of $HBr$ across the double bond fol

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phenol

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(B) The reaction proceeds as follows:$1$. The starting material is $6$-chlorocyclohex-$2$-en-$1$-one.$2$. Addition of $HBr$ across the double bond follows Markovnikov's rule,resulting in the formation of $6$-chloro-$3$-bromocyclohexan-$1$-one.$3$. Treatment with alcoholic $KOH$ $(alc. KOH)$ causes dehydrohalogenation (elimination of $HBr$ and $HCl$),leading to the formation of cyclohexa-$2,4$-dien-$1$-one.$4$. This intermediate undergoes tautomerization to form the more stable aromatic product,phenol $(C_6H_5OH)$.

The major product of the following reaction is

Similar Questions

Phenol reacts with $CHCl_3$ and $NaOH$ (at $340 \ K$) to give

Phenol is more acidic than:

The ascending order of acidity of the $-OH$ group in the following compounds is:
$A$. $Bu-OH$
$B$. $p$-nitrophenol
$C$. $p$-methoxyphenol
$D$. Phenol
$E$. $2,4$-dinitrophenol
Choose the correct answer from the options given below:

While separating a mixture of $o-$ and $p-$nitrophenols by steam distillation,name the isomer which will be steam volatile. Give reason.

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