The mass number of an anion,X^{3-},is 14. If | vedclass

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(B) The mass number $(A)$ is defined as the sum of the number of protons $(Z)$ and the number of neutrons $(n)$: $A = Z + n$.Given the mass number $A

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$7$

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(B) The mass number $(A)$ is defined as the sum of the number of protons $(Z)$ and the number of neutrons $(n)$: $A = Z + n$.Given the mass number $A = 14$.For the anion $X^{3-}$,the number of electrons is $10$. Since the anion is formed by gaining $3$ electrons,the number of protons $(Z)$ in the neutral atom $X$ is $Z = 10 - 3 = 7$.Using the mass number formula: $14 = 7 + n$.Therefore,the number of neutrons $n = 14 - 7 = 7$.

The mass number of an anion,$X^{3-}$,is $14$. If there are $10$ electrons in the anion,the number of neutrons in the nucleus of an atom of the element $X$ is:

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