The maximum height attained by a projectile when thrown at an angle $\theta$ with the horizontal is found to be half the horizontal range. Then $\theta$ is equal to

  • A
    $\tan^{-1}(2)$
  • B
    $\frac{\pi}{6}$
  • C
    $\frac{\pi}{4}$
  • D
    $\tan^{-1}(\frac{1}{2})$

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