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(C) The degree of unsaturation for $C_4H_6$ is $4 - (6/2) + 1 = 2$. This indicates the presence of two double bonds,one triple bond,or two rings,or a

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$9$

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(C) The degree of unsaturation for $C_4H_6$ is $4 - (6/2) + 1 = 2$. This indicates the presence of two double bonds,one triple bond,or two rings,or a combination of rings and double bonds.There are $9$ possible structural isomers for $C_4H_6$:$1$. $CH_3-CH_2-C\equiv CH$ (but$-1-$yne)$2$. $CH_3-C\equiv C-CH_3$ (but$-2-$yne)$3$. $CH_2=C=CH-CH_3$ (buta$-1,2-$diene)$4$. $CH_2=CH-CH=CH_2$ (buta$-1,3-$diene)$5$. $CH_2=C(CH_3)-CH=CH_2$ ($2$-methylpropa$-1,2-$diene)$6$. Cyclobutene$7$. $1-$Methylcyclopropene$8$. $3-$Methylcyclopropene$9$. MethylenecyclopropaneThus,the total number of structural isomers is $9$.

The maximum number of structural isomers possible for the hydrocarbon having the molecular formula $C_4H_6$ is:

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