The mean deviation from the mean of the data | vedclass

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(B) Step $1$: Calculate the mean $(\bar{x})$.$\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{(10 	imes 2) + (15 	imes 4) + (20 	imes 6) + (25 	im

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$5.12$

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(B) Step $1$: Calculate the mean $(\bar{x})$.$\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{(10 	imes 2) + (15 	imes 4) + (20 	imes 6) + (25 	imes 8) + (30 	imes 5)}{2 + 4 + 6 + 8 + 5} = \frac{20 + 60 + 120 + 200 + 150}{25} = \frac{550}{25} = 22$.Step $2$: Calculate the mean deviation about the mean $(	ext{M.D.}(\bar{x}))$.$	ext{M.D.}(\bar{x}) = \frac{\sum f_i |x_i - \bar{x}|}{\sum f_i}$.$|10 - 22| = 12, |15 - 22| = 7, |20 - 22| = 2, |25 - 22| = 3, |30 - 22| = 8$.$	ext{M.D.}(\bar{x}) = \frac{(2 	imes 12) + (4 	imes 7) + (6 	imes 2) + (8 	imes 3) + (5 	imes 8)}{25} = \frac{24 + 28 + 12 + 24 + 40}{25} = \frac{128}{25} = 5.12$.

$\text{Marks}$	$10$	$15$	$20$	$25$	$30$
$\text{Number of students}$	$2$	$4$	$6$	$8$	$5$

$x_i$	$15$	$21$	$27$	$30$	$35$
$f_i$	$3$	$5$	$6$	$7$	$8$

The mean deviation from the mean of the data given below is
$\text{Marks}$ $10$ $15$ $20$ $25$ $30$
$\text{Number of students}$ $2$ $4$ $6$ $8$ $5$

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The mean deviation from the mean of the data given below is$\text{Marks}$$10$$15$$20$$25$$30$$\text{Number of students}$$2$$4$$6$$8$$5$