The mean deviation from the mean of the discr | vedclass

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(D) Step $1$: Find the mean $(\bar{x})$ of the data.$\bar{x} = \frac{2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 22}{9} = \frac{99}{9} = 11$.Step $2$: Calcula

Vedclass · Accepted Answer

$6$

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(D) Step $1$: Find the mean $(\bar{x})$ of the data.$\bar{x} = \frac{2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 22}{9} = \frac{99}{9} = 11$.Step $2$: Calculate the absolute deviations from the mean $|x_i - \bar{x}|$.$|2 - 11| = 9$$|3 - 11| = 8$$|5 - 11| = 6$$|7 - 11| = 4$$|11 - 11| = 0$$|13 - 11| = 2$$|17 - 11| = 6$$|19 - 11| = 8$$|22 - 11| = 11$Step $3$: Calculate the mean of these absolute deviations.$	ext{Mean Deviation} = \frac{9 + 8 + 6 + 4 + 0 + 2 + 6 + 8 + 11}{9} = \frac{54}{9} = 6$.

Class Interval	$0$–$2$	$2$–$4$	$4$–$6$	$6$–$8$	$8$–$10$
Frequency	$1$	$3$	$4$	$1$	$2$

The mean deviation from the mean of the discrete data $2, 3, 5, 7, 11, 13, 17, 19, 22$ is

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Class Interval $0$–$2$ $2$–$4$ $4$–$6$ $6$–$8$ $8$–$10$
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