The median $AD$ of a triangle $ABC$ is perpendicular to $AB$. Then the value of $\tan A + 2\tan B$ is:

  • A
    $1$
  • B
    $0$
  • C
    $2$
  • D
    $3$

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$(C)$ $\frac{q+r}{p} < 2 \frac{\sqrt{\sin Q \sin R}}{\sin P}$
$(D)$ If $p < q$ and $p < r$,then $\cos Q > \frac{p}{r}$ and $\cos R > \frac{p}{q}$

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