The median class in the following frequency distribution is $\ldots \ldots \ldots \ldots .$
Class $10-25$ $25-40$ $40-55$ $55-70$ $70-85$ $85-100$
Frequency $5$ $21$ $21$ $8$ $25$ $20$

  • A
    $70-85$
  • B
    $25-40$
  • C
    $40-55$
  • D
    $55-70$

Explore More

Similar Questions

Find the median of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $2$ $6$ $8$ $16$ $20$ $18$ $16$ $14$

Difficult
View Solution

The lengths of $40$ leaves of a plant are measured correct to the nearest millimetre,and the data obtained is represented in the following table:
Length (in mm)Number of leaves
$118-126$$3$
$127-135$$5$
$136-144$$9$
$145-153$$12$
$154-162$$5$
$163-171$$4$
$172-180$$2$

Find the median length of the leaves.

Weekly income of $600$ families is tabulated below:
Weekly income Number of families
$0-1000$ $250$
$1000-2000$ $190$
$2000-3000$ $100$
$3000-4000$ $40$
$4000-5000$ $15$
$5000-6000$ $5$
Total $600$

Compute the median income (in $Rs.$).

$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years)Number of policy holders
Below $20$$2$
Below $25$$6$
Below $30$$24$
Below $35$$45$
Below $40$$78$
Below $45$$89$
Below $50$$92$
Below $55$$98$
Below $60$$100$

Difficult
View Solution

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times c$ for the median,$cf = \ldots \ldots \ldots$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo