The median of a triangle divides it into two:

Two sides of a triangle are of lengths $5\, cm$ and $1.5\, cm$. The length of the third side of the triangle cannot be (in $cm$):

In $\triangle PQR$,$\angle P = 70^{\circ}$ and $\angle R = 30^{\circ}$. Which side of this triangle is the longest? Give a reason for your answer.

The difference of any two sides of a triangle is $\ldots \ldots \ldots$ than the third side.

In $\triangle ABC$,$BC = AB$ and $\angle B = 80^{\circ}$. Then $\angle A$ is equal to: (in $^{\circ}$)

In $\Delta ABC$,$AD$ is a median. $P$ and $Q$ are the midpoints of $AB$ and $AD$ respectively. If $\operatorname{ar}(\Delta ABC) = 72 \, \text{cm}^2$,then $\operatorname{ar}(\Delta APQ) = \dots \text{cm}^2$.