The molar conductivities at infinite dilution | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Key Idea: Kohlrausch law of independent migration of ions can be used to calculate $\Delta_m^o$ for weak electrolytes such as acetic acid.Given:$\

Vedclass · Accepted Answer

$390.5 \ S \ cm^2 \ mol^{-1}$

Vedclass · Answer

(C) Key Idea: Kohlrausch law of independent migration of ions can be used to calculate $\Delta_m^o$ for weak electrolytes such as acetic acid.Given:$\Delta_{m(NaAc)}^o = 91 \ S \ cm^2 \ mol^{-1}$$\Delta_{m(HCl)}^o = 425.9 \ S \ cm^2 \ mol^{-1}$$\Delta_{m(NaCl)}^o = 126.4 \ S \ cm^2 \ mol^{-1}$Using Kohlrausch law,the molar conductivity of acetic acid is calculated as:$\Delta_{m(CH_3COOH)}^o = \Delta_{m(CH_3COONa)}^o + \Delta_{m(HCl)}^o - \Delta_{m(NaCl)}^o$$= (91.0 + 425.9 - 126.4) \ S \ cm^2 \ mol^{-1}$$= 390.5 \ S \ cm^2 \ mol^{-1}$

The molar conductivities at infinite dilution for sodium acetate,$HCl$ and $NaCl$ are $91 \ S \ cm^2 \ mol^{-1}$,$425.9 \ S \ cm^2 \ mol^{-1}$ and $126.4 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of acetic acid at infinite dilution is

Similar Questions

With dilution,the conductivity of a solution $—$

$A$ conductivity cell has two electrodes $18 \ mm$ apart and having cross-sectional area $2.0 \ cm^2$. What is the value of the cell constant (in $cm^{-1}$)?

The dissociation constant of acetic acid is $1.6 \times 10^{-5}$ and molar conductance at infinite dilution is $380 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acid solution is

What is the molar conductivity at infinite dilution of $CaCl_{2}$,if the molar conductivity of $Ca^{2+}$ ion and $Cl^{-}$ ion at infinite dilution is $119$ and $71 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ respectively?

The ionic conductivity of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ ohm^{-1} cm^2 eq^{-1}$ respectively. The equivalent conductivity of $BaCl_2$ at infinite dilution (in $ohm^{-1} cm^2 eq^{-1}$) would be $:-$

Vedclass Test Series

Exam Paper Generator

Online Exam Module