The molar specific heat of an ideal gas at constant pressure and constant volume is $C_{p}$ and $C_{v}$ respectively. If $R$ is the universal gas constant and $\gamma = \frac{C_p}{C_v}$,then $C_v =$

  • A
    $\frac{1-\gamma}{1+\gamma}$
  • B
    $\frac{1+\gamma}{1-\gamma}$
  • C
    $\frac{\gamma-1}{R}$
  • D
    $\frac{R}{\gamma-1}$

Explore More

Similar Questions

If the difference between the specific heats of a gas is $4150 \, J/kg \cdot K$ and the ratio of specific heats is $1.4$,then the specific heat at constant volume is ...... $J/kg \cdot K$.

The molar specific heats of an ideal gas at constant pressure and constant volume are denoted by $C_p$ and $C_v$ respectively. If $\gamma = \frac{C_p}{C_v}$ and $R$ is the universal gas constant,then $C_v$ is equal to:

The ratio of two specific heats $\frac{C_P}{C_V}$ of $CO$ is

One mole of an ideal monoatomic gas is heated at a constant pressure from $0^{\circ} C$ to $100^{\circ} C$. The change in the internal energy of the gas is (Given, $R = 8.32 \text{ J mol}^{-1} \text{ K}^{-1}$):

If the ratio of specific heat of a gas at constant pressure to that at constant volume is $\gamma$,the change in internal energy of a mass of gas,when the volume changes from $V$ to $2V$ at constant pressure $p$,is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo