The molarity of a solution made by mixing 50 | vedclass

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Question

(C) The normality of the final solution is calculated using the dilution formula: $N_1V_1 = N_2V_2$.Here,$N_1 = 36 \ N$,$V_1 = 50 \ mL$,and $V_2 = 50

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) The normality of the final solution is calculated using the dilution formula: $N_1V_1 = N_2V_2$.Here,$N_1 = 36 \ N$,$V_1 = 50 \ mL$,and $V_2 = 50 \ mL + 50 \ mL = 100 \ mL$.$36 	imes 50 = N_2 	imes 100$.$N_2 = \frac{36 	imes 50}{100} = 18 \ N$.For $H_2SO_4$,the n-factor is $2$. The relationship between normality and molarity is $N = M 	imes 	ext{n-factor}$.$18 = M 	imes 2$,so $M = 9 \ M$.

The molarity of a solution made by mixing $50 \ mL$ of conc. $H_2SO_4$ $(36 \ N)$ with $50 \ mL$ of water is ...... $M$.

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