The moment of inertia of a circular ring of radius $r$ and mass $M$ about its diameter is:

  • A
    $\frac{2}{5} Mr^{2}$
  • B
    $\frac{Mr^{2}}{4}$
  • C
    $\frac{Mr^{2}}{2}$
  • D
    $\frac{Mr^{2}}{12}$

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Similar Questions

One solid sphere $A$ and another hollow sphere $B$ have the same mass and the same outer radii. Their moments of inertia about their diameters are $I_{A}$ and $I_{B}$ respectively. Which of the following relations is correct?

$A$ thin metal rod of mass $M$ and length $L$ is cut into four equal parts by cutting it perpendicular to its length. If the moment of inertia of the rod about an axis passing through its centre and perpendicular to its length is $I$,then the moment of inertia of each part about an axis passing through its own centre and perpendicular to its length is:

$A$ wire of mass $M$ and length $L$ is bent in the form of a circular ring. The moment of inertia of the ring about its axis is

The moment of inertia depends on:

Find the moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane.

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