The momentum p of an object varies with time | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Newton's second law of motion,the force $F$ is given by the rate of change of momentum:$F = \frac{dp}{dt}$This means the force $F$ is

Vedclass · Accepted Answer

Vedclass · Answer

(A) According to Newton's second law of motion,the force $F$ is given by the rate of change of momentum:$F = \frac{dp}{dt}$This means the force $F$ is equal to the slope of the $p-t$ graph.$1$. From $t = 0$ to $t = 2 \ s$,the momentum increases linearly from $0$ to $10 \ kg \ m/s$. The slope is constant and positive:$F = \frac{10 - 0}{2 - 0} = 5 \ N$$2$. From $t = 2$ to $t = 6 \ s$,the momentum is constant at $10 \ kg \ m/s$. The slope is zero:$F = \frac{10 - 10}{6 - 2} = 0 \ N$$3$. From $t = 6$ to $t = 8 \ s$,the momentum decreases linearly from $10$ to $0 \ kg \ m/s$. The slope is constant and negative:$F = \frac{0 - 10}{8 - 6} = -5 \ N$Comparing these values with the given options,the graph in Option $A$ correctly represents these force values over time.

The momentum $p$ of an object varies with time $(t)$ as shown in the figure. The corresponding force $(F)$-time $(t)$ graph is

Similar Questions

Two balls each of mass $250 \ g$ moving in opposite directions each with a speed $16 \ m \ s^{-1}$ collide and rebound with the same speeds. The impulse imparted to one ball due to the other is

$1000$ small balls,each weighing $1 \text{ g}$,strike $1 \text{ cm}^2$ of area per second with a velocity of $50 \text{ m/s}$ in a normal direction and rebound with the same velocity. The value of pressure on the surface will be:

When the speed of a moving body is doubled:

$A$ particle of mass $m \, kg$ moving with a velocity $v \, m/s$ strikes a surface as shown in the figure and rebounds with the same speed. The magnitude of the change in momentum is:

$A$ force of $50\, dynes$ acts on a body of mass $5\, g$ which is at rest for an interval of $3\, seconds$. The impulse is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module