The most stable carbocation among the followi | vedclass

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(A) The stability of carbocations is determined by the inductive effect $(+I)$ and hyperconjugation (number of $\alpha-H$ atoms).$1$. $(CH_{3})_{3}C^{

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$(CH_{3})_{3}C^{+}$

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(A) The stability of carbocations is determined by the inductive effect $(+I)$ and hyperconjugation (number of $\alpha-H$ atoms).$1$. $(CH_{3})_{3}C^{+}$ is a tertiary $(3^{\circ})$ carbocation with $9$ $\alpha-H$ atoms.$2$. $CH_{3}CH_{2}CH^{+}CH_{2}CH_{3}$ is a secondary $(2^{\circ})$ carbocation with $4$ $\alpha-H$ atoms.$3$. $CH_{3}CH^{+}CH_{2}CH_{2}CH_{3}$ is a secondary $(2^{\circ})$ carbocation with $3$ $\alpha-H$ atoms.$4$. $CH_{3}CH_{2}CH_{2}^{+}$ is a primary $(1^{\circ})$ carbocation with $2$ $\alpha-H$ atoms.Since the stability order is $3^{\circ} > 2^{\circ} > 1^{\circ}$, the tertiary carbocation $(CH_{3})_{3}C^{+}$ is the most stable.

The most stable carbocation among the following is:

Similar Questions

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

The central carbon atom of a free radical contains

The order of circled $C-H$ bond dissociation energy in the following compounds is:

The stability of the carbocations follows the order:

Which of the following compounds forms the most stable carbocation: $(CH_3)_3C-Br$,$(C_6H_5)_3CBr$,$(C_6H_5)_2CHBr$,and $C_6H_5CH_2Br$?

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