The multiplicative inverse of matrix begin{bm | vedclass

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(D) Let $A = \begin{bmatrix} 2 & 1 \ 7 & 4 \end{bmatrix}$.To find the inverse $A^{-1}$,we use the formula $A^{-1} = \frac{1}{|A|} 	ext{adj}(A)$.Firs

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$\begin{bmatrix} 4 & -1 \ -7 & 2 \end{bmatrix}$

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(D) Let $A = \begin{bmatrix} 2 & 1 \ 7 & 4 \end{bmatrix}$.To find the inverse $A^{-1}$,we use the formula $A^{-1} = \frac{1}{|A|} 	ext{adj}(A)$.First,calculate the determinant $|A| = (2 	imes 4) - (1 	imes 7) = 8 - 7 = 1$.Next,find the adjoint of $A$ by swapping the diagonal elements and changing the signs of the off-diagonal elements:$	ext{adj}(A) = \begin{bmatrix} 4 & -1 \ -7 & 2 \end{bmatrix}$.Therefore,$A^{-1} = \frac{1}{1} \begin{bmatrix} 4 & -1 \ -7 & 2 \end{bmatrix} = \begin{bmatrix} 4 & -1 \ -7 & 2 \end{bmatrix}$.Thus,the correct option is $D$.

The multiplicative inverse of matrix $\begin{bmatrix} 2 & 1 \\ 7 & 4 \end{bmatrix}$ is

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