(B) For a freely falling body, the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$, the equation becomes $v

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a straight line passing through the origin.

(B) For a freely falling body, the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$, the equation becomes $v = gt$. Here, $g$ is the acceleration due to gravity, which is a constant ($g \approx 9.8 \ m/s^2$ or $10 \ m/s^2$). This equation $v = gt$ is of the form $y = mx$, where $y$ represents speed, $x$ represents time, and $m = g$ is the slope. Since there is no constant term (intercept), the graph is a straight line passing through the origin $(0, 0)$. Therefore, the correct option is $B$.

Class 11 Physics Motion in a Straight Line Motion Under Gravity

Easy

The nature of a graph drawn for a freely falling body with time on the $x$-axis and speed on the $y$-axis is (Assuming initial speed to be zero.)

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A
a straight line with positive $y$-axis intercept.
B
a straight line passing through the origin.
C
a parabola.
D
a straight line parallel to $y$-axis with positive $x$-axis intercept.

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Motion in a Straight Line

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Motion Under Gravity

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The nature of a graph drawn for a freely falling body with time on the $x$-axis and speed on the $y$-axis is (Assuming initial speed to be zero.)

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