(A) four-digit number has four places: $ABCD$.Given that the first digit $A$ is fixed as $4$,there is only $1$ way to fill this place.The last digit $

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(A) four-digit number has four places: $ABCD$.Given that the first digit $A$ is fixed as $4$,there is only $1$ way to fill this place.The last digit $D$ can be either $0$ or $5$,so there are $2$ ways to fill this place.The second digit $B$ can be any digit from $0$ to $9$,so there are $10$ ways.The third digit $C$ can be any digit from $0$ to $9$,so there are $10$ ways.Therefore,the total number of such four-digit numbers is $1 \times 10 \times 10 \times 2 = 200$.

Class 11 Mathematics Permutations and Combinations Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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The number of all four-digit numbers which begin with $4$ and end with either $0$ or $5$ is:

AP EAMCET 2023 All AP EAMCET

A
$200$
B
$64$
C
$256$
D
$32$

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Permutations and Combinations

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Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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The number of all four-digit numbers which begin with $4$ and end with either $0$ or $5$ is:

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