The number of electrons moving per second thr | vedclass

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(C) Step $1$: Calculate the current $I$ using the power formula $P = VI$.$I = \frac{P}{V} = \frac{60 	ext{ W}}{120 	ext{ V}} = 0.5 	ext{ A}$.Step $

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$3.1 	imes 10^{18}$

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(C) Step $1$: Calculate the current $I$ using the power formula $P = VI$.$I = \frac{P}{V} = \frac{60 	ext{ W}}{120 	ext{ V}} = 0.5 	ext{ A}$.Step $2$: Relate current to the number of electrons $n$ moving per second using $I = \frac{q}{t} = \frac{ne}{t}$.Since $t = 1 	ext{ s}$, $n = \frac{I}{e}$.Step $3$: Substitute the values to find $n$.$n = \frac{0.5 	ext{ A}}{1.6 	imes 10^{-19} 	ext{ C}} = \frac{5}{16} 	imes 10^{19} = 0.3125 	imes 10^{19} = 3.125 	imes 10^{18}$.Thus, the number of electrons is nearly $3.1 	imes 10^{18}$.

The number of electrons moving per second through the filament of a lamp of $60 \text{ W}$ operating at $120 \text{ V}$ is nearly $(e = 1.6 \times 10^{-19} \text{ C})$

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