Two identical electric lamps marked 500, W, 2 | vedclass

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Question

(A) First,calculate the resistance $R$ of each lamp using the rated values:$R = \frac{V^2}{P} = \frac{220^2}{500} = \frac{48400}{500} = 96.8\, \Omega$

Vedclass · Accepted Answer

$\frac{125}{4}\, W$

Vedclass · Answer

(A) First,calculate the resistance $R$ of each lamp using the rated values:$R = \frac{V^2}{P} = \frac{220^2}{500} = \frac{48400}{500} = 96.8\, \Omega$Since the two identical lamps are connected in series to a $110\, V$ source,the voltage across each lamp is $V' = \frac{110}{2} = 55\, V$.The power consumed by each lamp is given by:$P' = \frac{(V')^2}{R} = \frac{55^2}{96.8} = \frac{3025}{96.8} = 31.25\, W$Alternatively,using the ratio method:$P' = \left( \frac{V'}{V} ight)^2 	imes P = \left( \frac{55}{220} ight)^2 	imes 500 = \left( \frac{1}{4} ight)^2 	imes 500 = \frac{1}{16} 	imes 500 = \frac{125}{4}\, W$

Two identical electric lamps marked $500\, W, 220\, V$ are connected in series and then joined to a $110\, V$ line. The power consumed by each lamp is

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