The number of linkage isomers possible for [P | vedclass

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(A) The complex $[Pt(en)(NO_2)_2]$ contains ambidentate ligands $(NO_2^-)$,which can coordinate through either the $N$ atom or the $O$ atom.This leads

Vedclass · Accepted Answer

$3$

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(A) The complex $[Pt(en)(NO_2)_2]$ contains ambidentate ligands $(NO_2^-)$,which can coordinate through either the $N$ atom or the $O$ atom.This leads to the formation of linkage isomers based on the coordination mode of the two $NO_2^-$ ligands:$I$. $[Pt(en)(NO_2)_2]$ (both $NO_2^-$ coordinated through $N$)$II$. $[Pt(en)(NO_2)(ONO)]$ (one $NO_2^-$ through $N$,one through $O$)$III$. $[Pt(en)(ONO)_2]$ (both $NO_2^-$ coordinated through $O$)Thus,there are $3$ possible linkage isomers.

The number of linkage isomers possible for $[Pt(en)(NO_2)_2]$ is :

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