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(D) To determine the number of molecules with a lone pair on the central atom,we analyze the hybridization and structure of each molecule:$1$. $BF_3$:

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$5$

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(D) To determine the number of molecules with a lone pair on the central atom,we analyze the hybridization and structure of each molecule:$1$. $BF_3$: Central atom $B$ has $3$ valence electrons,all involved in bonding. Lone pairs = $0$.$2$. $SF_4$: Central atom $S$ has $6$ valence electrons,$4$ used for bonding,$1$ lone pair remains.$3$. $SiCl_4$: Central atom $Si$ has $4$ valence electrons,all used for bonding. Lone pairs = $0$.$4$. $XeF_4$: Central atom $Xe$ has $8$ valence electrons,$4$ used for bonding,$2$ lone pairs remain.$5$. $NCl_3$: Central atom $N$ has $5$ valence electrons,$3$ used for bonding,$1$ lone pair remains.$6$. $XeF_6$: Central atom $Xe$ has $8$ valence electrons,$6$ used for bonding,$1$ lone pair remains.$7$. $PCl_5$: Central atom $P$ has $5$ valence electrons,all used for bonding. Lone pairs = $0$.$8$. $HgCl_2$: Central atom $Hg$ has $2$ valence electrons,all used for bonding. Lone pairs = $0$.$9$. $SnCl_2$: Central atom $Sn$ has $4$ valence electrons,$2$ used for bonding,$1$ lone pair remains.The molecules with at least one lone pair are $SF_4, XeF_4, NCl_3, XeF_6, SnCl_2$. The total count is $5$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

The number of molecules having a lone pair of electrons on the central atom in the following is: $BF_3, SF_4, SiCl_4, XeF_4, NCl_3, XeF_6, PCl_5, HgCl_2, SnCl_2$

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