The number of possible organobromine compound | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $NBS$ $(N-bromosuccinimide)$ performs allylic bromination via a free radical mechanism. For $but-1-ene$ $(CH_3-CH_2-CH=CH_2)$, the allylic hydroge

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) $NBS$ $(N-bromosuccinimide)$ performs allylic bromination via a free radical mechanism. For $but-1-ene$ $(CH_3-CH_2-CH=CH_2)$, the allylic hydrogen is at the $C-3$ position. Abstraction of this hydrogen generates an allylic radical: $CH_3-\dot{C}H-CH=CH_2 \leftrightarrow CH_3-CH=CH-\dot{C}H_2$. Reaction of this resonance-stabilized radical with $Br \cdot$ leads to two constitutional isomers: $1$. $3-bromobut-1-ene$ $(CH_3-CH(Br)-CH=CH_2)$, which contains a chiral center and thus exists as a pair of enantiomers ($d$ and $l$). $2$. $1-bromobut-2-ene$ $(CH_3-CH=CH-CH_2Br)$, which exhibits geometrical isomerism ($cis$ and $trans$). Therefore, the total number of possible organobromine compounds is $2$ (enantiomers)   $2$ (geometrical isomers) = $4$.

The number of possible organobromine compounds which can be obtained in the allylic bromination of $but-1-ene$ with $N-bromosuccinimide$ $(NBS)$ is

Similar Questions

Two alkenes,$X$ ($91\%$ yield) and $Y$ ($9\%$ yield),are formed when the following compound is heated:
The structures of $X$ and $Y$,respectively,are:

$A$ compound $X$ absorbs $2$ moles of hydrogen and $X$ upon oxidation with $KMnO_4 \mid H^{+}$ gives the products shown below:
$CH_3-CO-CH_3$,$CH_3-COOH$ and $CH_3-CO-CH_2-CH_2-COOH$.
The total number of $\sigma$ bonds present in the compound $X$ is . . . . . .

$CH_3-CH=CH-CH_3 \xrightarrow[R_2O_2, \Delta]{HBr} \text{ (Anti-Markownikoff's addition)}$
Comment on the optical activity of the products.

Ozonolysis of which olefin yields $CH_3CH_2CHO$ and $CH_3CHO$?

Product $(A)$ of the above reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module