The number of rotational degrees of freedom of a diatomic molecule is:

The gases carbon monoxide $(CO)$ and nitrogen $(N_{2})$ at the same temperature have kinetic energies $E_{1}$ and $E_{2}$ respectively. Then

For two different gases $X$ and $Y,$ having degrees of freedom $f_1$ and $f_2$ and molar heat capacities at constant volume $C_{v_1}$ and $C_{v_2}$ respectively, for an adiabatic process, the $\ln P$ versus $\ln V$ graph is plotted as shown:

If the degrees of freedom of a gas molecule is $6$,then the total internal energy of the gas molecule at a temperature of $47^{\circ} C$ (in $eV$) is (Boltzmann constant $= 1.38 \times 10^{-23} \ J \ K^{-1}$)

For a triatomic gas molecule,if the degrees of freedom for translation,rotation,and vibration are considered,then $C_P/C_V = ?$

The number of rotational degrees of freedom of a monatomic molecule is