The number of stereoisomers possible for the | vedclass

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(D) The given compound is $CH_3-CH=CH-CH(OH)-CH_3$. It contains one chiral carbon atom $(C^*)$,which leads to $2^1 = 2$ optical isomers. It also conta

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$4$

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(D) The given compound is $CH_3-CH=CH-CH(OH)-CH_3$. It contains one chiral carbon atom $(C^*)$,which leads to $2^1 = 2$ optical isomers. It also contains a carbon-carbon double bond $(C=C)$,which allows for geometrical isomerism (cis and trans forms),resulting in $2$ geometrical isomers. Since the chiral center and the double bond are independent,the total number of stereoisomers is calculated as $2 	imes 2 = 4$.

The number of stereoisomers possible for the following compound is $CH_3-CH=CH-CH(OH)-CH_3$.

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