The optically inactive compound from the following is

Explain how substitution and elimination reactions compete in the same reaction.

Consider the $S_N1$ solvolysis of the following halides in aqueous formic acid:
$(I)$ $CH_3-CH(CH_3)-CH(Br)-CH_3$
$(II)$ $CH_3-C(CH_3)(Br)-CH_3$
$(III)$ $C_6H_5-CH(Br)-C_6H_5$
$(IV)$ $C_6H_5-CH(Br)-CH_3$
Which one of the following is the correct sequence of the halides given above in the decreasing order of their reactivity?

Which among the following is $NOT$ a correct statement about $S_{N}1$ reaction?

The product $A$ of the following sequence of reactions is:
Ethylbenzene $\xrightarrow[(b) Cl_2, \Delta]{(a) Br_2, Fe}$ $\xrightarrow{(c) alc. KOH} 'A' \text{ (Major product)}$

The ascending order of relative rate of solvolysis of the following compounds is: