(B) Let the oxidation number of $Cr$ be $x$.In the complex $[Cr(H_2O)_4Cl_2]^+$,the oxidation state of $H_2O$ is $0$ and $Cl$ is $-1$.The overall char

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(B) Let the oxidation number of $Cr$ be $x$.In the complex $[Cr(H_2O)_4Cl_2]^+$,the oxidation state of $H_2O$ is $0$ and $Cl$ is $-1$.The overall charge on the complex is $+1$.Therefore,the equation is: $x + 4(0) + 2(-1) = +1$.$x - 2 = +1$.$x = +3$.Thus,the oxidation number of $Cr$ is $+3$.