The oxidation number of iron in potassium fer | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical formula for potassium ferrocyanide is $K_4[Fe(CN)_6]$.Let the oxidation number of iron $(Fe)$ be $x$.The oxidation number of potassiu

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The chemical formula for potassium ferrocyanide is $K_4[Fe(CN)_6]$.Let the oxidation number of iron $(Fe)$ be $x$.The oxidation number of potassium $(K)$ is $+1$ and the cyanide ligand $(CN)$ is $-1$.Applying the rule that the sum of oxidation states in a neutral complex is zero:$4(+1) + x + 6(-1) = 0$$4 + x - 6 = 0$$x - 2 = 0$$x = +2$.Therefore,the oxidation number of iron is $2$.

The oxidation number of iron in potassium ferrocyanide is

Similar Questions

The $IUPAC$ name for the complex $[Co(NH_3)_5(NO_2)]Cl_2$ is:

What is the oxidation state of copper in the $[Cu(NH_3)_4]^{2+}$ ion?

What is the oxidation state of the central metal ion in the $\left[ Fe(CN)_6 \right]^{4-}$ complex?

State the $IUPAC$ name of the following complex: $[CuCl_{2}(CH_{3}NH_{2})_{2}]$

The $IUPAC$ name of $[Ni(NH_3)_4][NiCl_4]$ is .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module