The oxidation states of three carbon atoms in | vedclass

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(A) The structure of carbon suboxide $(C_3O_2)$ is $O=C=C=C=O$. In this structure, the two terminal carbon atoms are bonded to oxygen atoms. Since the

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$+2, 0, +2$

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(A) The structure of carbon suboxide $(C_3O_2)$ is $O=C=C=C=O$. In this structure, the two terminal carbon atoms are bonded to oxygen atoms. Since the oxidation state of oxygen is $-2$, each terminal carbon atom must have an oxidation state of $+2$ to balance the bond. The central carbon atom is bonded to two other carbon atoms, and since there is no electronegativity difference between identical atoms, its oxidation state is $0$. Thus, the oxidation states are $+2, 0, +2$.

The oxidation states of three carbon atoms in carbon suboxide $(C_3O_2)$ respectively are

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