The passage of current liberates $H_2$ at cathode and $Cl_2$ at anode. The solution is

  • A
    Copper chloride in water
  • B
    $NaCl$ in water
  • C
    $H_2SO_4$
  • D
    Water

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Similar Questions

Write the reactions for the following:
$A$. Electrolytic reaction of concentrated and dilute solution of $H_2SO_4$.
$B$. Oxidation reaction of $SO_4^{2-}$.

On electrolysing a solution of dilute $H_2SO_4$ between platinum electrodes,the gas evolved at the anode is

Two statements are given below.
Statement $I$ : Molten $NaCl$ is electrolysed using $Pt$ electrodes. $Cl_2$ is liberated at anode.
Statement $II$ : Aqueous $CuSO_4$ is electrolysed using $Pt$ electrodes. $O_2$ is liberated at cathode.
The correct answer is

Extraction of chlorine from brine solution is based on

Electrolytes,when dissolved in water,dissociate into ions because:

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