The percentage of $p$-character of the hybrid orbitals in graphite and diamond are respectively
- A$50$ and $75$
- B$67$ and $75$
- C$33$ and $75$
- D$33$ and $25$
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Which orbital is more electronegative among $sp$,$sp^2$,and $sp^3$? Why?
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View SolutionThe hybridisation in $BF_3$ molecule is
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View SolutionWhat is the hybridization of $C$ atoms in graphite?
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View SolutionMatch the following List-$I$ (Hybridisation) with List-$II$ (Shape):
List-$I$ (Hybridisation) List-$II$ (Shape) $A$. $dsp^2$ $I$. Square planar $B$. $sp^3$ $II$. Tetrahedral $C$. $d^2sp^3$ $III$. Octahedral $D$. $sp^3d$ $IV$. Trigonal bipyramidal
| List-$I$ (Hybridisation) | List-$II$ (Shape) |
|---|---|
| $A$. $dsp^2$ | $I$. Square planar |
| $B$. $sp^3$ | $II$. Tetrahedral |
| $C$. $d^2sp^3$ | $III$. Octahedral |
| $D$. $sp^3d$ | $IV$. Trigonal bipyramidal |
The compounds with $sp^2$ hybridized central atom among the following are:
$(A)$ $H_2CO_3$
$(B)$ $SiF_4$
$(C)$ $BF_3$
$(D)$ $HClO_2$
$(A)$ $H_2CO_3$
$(B)$ $SiF_4$
$(C)$ $BF_3$
$(D)$ $HClO_2$
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