The perimeter of square ABCD is 20. Find AC. | vedclass

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(B) The perimeter of a square is given by $4 	imes 	ext{side}$.Given,$4 	imes 	ext{side} = 20$.Therefore,$	ext{side} = 20 / 4 = 5$.In a square $A

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$5$

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(B) The perimeter of a square is given by $4 	imes 	ext{side}$.Given,$4 	imes 	ext{side} = 20$.Therefore,$	ext{side} = 20 / 4 = 5$.In a square $ABCD$,the diagonal $AC$ forms a right-angled triangle $ABC$ with sides $AB$ and $BC$.By the Pythagorean theorem,$AC^2 = AB^2 + BC^2$.Since $AB = BC = 5$,we have $AC^2 = 5^2 + 5^2 = 25 + 25 = 50$.Thus,$AC = \sqrt{50} = \sqrt{25 	imes 2} = 5\sqrt{2}$.

The perimeter of square $ABCD$ is $20$. Find $AC$. (in $\sqrt{2}$)

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