The period of oscillation of a simple pendulu | vedclass

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(A) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$,where $l$ is the length of the pendulum and $g$ is the

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Greater than $T$

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(A) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$,where $l$ is the length of the pendulum and $g$ is the acceleration due to gravity.As we go inside a mine (below the Earth's surface),the effective acceleration due to gravity $g$ decreases.Since $T \propto \frac{1}{\sqrt{g}}$,a decrease in the value of $g$ leads to an increase in the time period $T$.Therefore,the period of oscillation inside a mine will be greater than $T$.

The period of oscillation of a simple pendulum of constant length at the Earth's surface is $T$. Its period inside a mine is

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