The phase difference between input and output voltages of a $CE$ (common emitter) amplifier circuit is........$^o$.

In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always

In a common emitter amplifier,the input resistance is $1000 \Omega$,the peak value of the input signal voltage is $5 mV$,and $\beta = 60$. The peak value of the output current is:

If ${l_1}, {l_2}, {l_3}$ are the lengths of the emitter,base,and collector of a transistor,respectively,then:

$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

An $npn$ transistor operates as a common emitter amplifier,with a power gain of $60\, dB$. The input circuit resistance is $100\,\Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ is: